Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Consider the following C function.int strg(ch...
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Consider the following C function.
int strg(char *str)
{
static int temp=0;
if(*str!=NULL)
{
temp++;
strg(++str);
}
else
{
return temp;
}
}
What is the output of strg(abcabcbb)?
Correct answer is '8'. Can you explain this answer?
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Most Upvoted Answer
Consider the following C function.int strg(char *str){static int temp=...
Explanation:
The given C function 'strg' takes a string as input and recursively counts the number of characters in the string until it reaches the end of the string. The static variable 'temp' is used to store the count of characters.
Execution:
When the function 'strg' is called with the string "abcabcbb", the following steps are executed:
1. The function is called with the string "abcabcbb".
2. The first character of the string is 'a', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
3. The function 'strg' is called again with the remaining string "bcabcbb".
4. The first character of the string is 'b', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
5. The function 'strg' is called again with the remaining string "cabcbb".
6. The first character of the string is 'c', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
7. The function 'strg' is called again with the remaining string "abcbb".
8. The first character of the string is 'a', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
9. The function 'strg' is called again with the remaining string "bcbb".
10. The first character of the string is 'b', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
11. The function 'strg' is called again with the remaining string "cbb".
12. The first character of the string is 'c', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
13. The function 'strg' is called again with the remaining string "bb".
14. The first character of the string is 'b', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
15. The function 'strg' is called again with the remaining string "b".
16. The first character of the string is 'b', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
17. The function 'strg' is called again with the remaining string "".
18. The first character of the string is NULL, so the 'else' part of the function is executed.
19. The value of 'temp', which is 8, is returned.
Therefore, the output of the function 'strg("abcabcbb")' is 8.
The given C function 'strg' takes a string as input and recursively counts the number of characters in the string until it reaches the end of the string. The static variable 'temp' is used to store the count of characters.
Execution:
When the function 'strg' is called with the string "abcabcbb", the following steps are executed:
1. The function is called with the string "abcabcbb".
2. The first character of the string is 'a', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
3. The function 'strg' is called again with the remaining string "bcabcbb".
4. The first character of the string is 'b', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
5. The function 'strg' is called again with the remaining string "cabcbb".
6. The first character of the string is 'c', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
7. The function 'strg' is called again with the remaining string "abcbb".
8. The first character of the string is 'a', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
9. The function 'strg' is called again with the remaining string "bcbb".
10. The first character of the string is 'b', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
11. The function 'strg' is called again with the remaining string "cbb".
12. The first character of the string is 'c', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
13. The function 'strg' is called again with the remaining string "bb".
14. The first character of the string is 'b', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
15. The function 'strg' is called again with the remaining string "b".
16. The first character of the string is 'b', which is not equal to NULL. So, the 'temp' variable is incremented by 1.
17. The function 'strg' is called again with the remaining string "".
18. The first character of the string is NULL, so the 'else' part of the function is executed.
19. The value of 'temp', which is 8, is returned.
Therefore, the output of the function 'strg("abcabcbb")' is 8.
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Community Answer
Consider the following C function.int strg(char *str){static int temp=...
This question is related to recursion. hence loop itself.
because function strg calling itself with parameters. outer function strg (char *str) read single character starting from first character and function strg (++str) is incredible. there is 8 character. hence loop executive 8 time and function return value 8. hence answer is 8.
because function strg calling itself with parameters. outer function strg (char *str) read single character starting from first character and function strg (++str) is incredible. there is 8 character. hence loop executive 8 time and function return value 8. hence answer is 8.
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Consider the following C function.int strg(char *str){static int temp=0;if(*str!=NULL){temp++;strg(++str);}else{return temp;}}What is the output of strg(abcabcbb)?Correct answer is '8'. Can you explain this answer?
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